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Force acting on a body due to gravity is given by, f = mg Where f is the force acting on the body, g is the acceleration due to gravity, m is mass of the body. According to the universal law of gravitation, f = GmM/(r+h)2 Where, 1. f = force between two bodies, 2. G = universal gravitational constant (6.67×10-11 … See more Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s2. It has both magnitude and direction, hence, it’s a vector quantity. Acceleration due to gravity is represented … See more Gravity is the force with which the earth attracts a body towards its centre. Let us consider two bodies of masses ma and mb. Under the … See more Acceleration due to Gravity at a height (h) from the surface of the earth Consider a test mass (m) at a height (h) from the surface of the earth. Now, the force acting on the test mass due … See more Earth as assumed to be a uniform solid spherewith a mean density. We know that, Density = mass/volume Then, ρ = M/[4/3 πR3] ⇒ M = ρ × [4/3 πR3] We know that, g = GM/R2. On substituting the values of M we get, g = 4/3 [πρRG] … See more Web(booklet) e.g. Class-11 Chemistry book contain three modules Module-1 (Physical Chemistry), Module-2 ... Physics for NEET/ JEE Main, Class 11 & 12, AIIMS, BITSAT … WebPhysicswallah Live Courses for JEE, NEET & Class 6,7,8,9,10,11,12 NCERT Solutions THE MOST RELIABLE LEARNING PLATFORM Learn from our best faculty. +91 - Explore Exam … city of york fire department