Webcalculus Let g (x) = ∫_0^x f (t) dt where f is the function. (a) Estimate g (0), g (4), g (6), and g (8). (b) Find the largest open interval on which g is increasing. Find the largest open interval on which g is decreasing. (c) Identify any extrema of g. (d) Sketch the rough graph of g. 1 / 2 WebNov 18, 2015 · these can be mapped onto a sine graph (x-axis is the angles in degrees, y-axis is opposite side height), OK. F = ( α, y ( α)) = ( α, sin ( α)) and should replicate the circle's curve but mirrored. You probably thought ( x, y ( α ( x)), where y ( α ( x)) = y ( arccos ( x)) = sin ( arccos ( x)) = 1 − cos ( arccos ( x)) 2 = 1 − x 2
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WebNov 25, 2013 · A = π r 2 or since it is only a Half-Circle and since it is below the x-axis it has to be negative: A = ∫ 10 30 g ( x) d x = π r 2 2 = − 50 π Before we can complete the 3rd part of the question you have to find: ∫ 30 35 g ( x) d x using the same concept as in part1, the following is also true here: 1 2 b h therefore: WebNov 18, 2015 · Because the height of these opposite sides equals the sine of the angles, these can be mapped onto a sine graph (x-axis is the angles in degrees, y-axis is … inc byte ptr
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WebThe middle of the semicircle is located at (h, k).; The semicircle has a radius of √r 2 = r.; a is generally 1 or -1; however, other dilations are possible.. If a is positive the top of the circle is present (concave down).; If a is negative the bottom of the circle is present (concave up).; All semicircle graphs have the same shape, they are just transformed (dilated and … WebSep 18, 2024 · It's also easy to rule out the graph on the left as f as the other graphs all have multiple roots. If the tangent slope of the first graph only hits 0 at one spot, so the graph of the derivative should only have 1 root crossing the x-axis. WebJan 11, 2024 · The \frac {1} {2} 21 and 2 cancel each other out, so you can simplify to get this perimeter of a semicircle formula. Perimeter of semicircle formula P=\pi r+d P = πr + d Using the substitution property of equality, you can also replace diameter with radius throughout: P=\frac {1} {2} (2\pi r)+2r P = 21 (2πr) + 2r P=\pi r+2r P = πr + 2r inc by laws